{"id":17961,"date":"2024-05-12T17:38:14","date_gmt":"2024-05-12T17:38:14","guid":{"rendered":"https:\/\/soicau4008.minhngocxoso.com\/?p=17961"},"modified":"2024-05-12T17:38:14","modified_gmt":"2024-05-12T17:38:14","slug":"5-phuong-phap-soi-cau-lo-de-hieu-qua-va-nhanh-chong","status":"publish","type":"post","link":"https:\/\/dichvuxosovip.com\/5-phuong-phap-soi-cau-lo-de-hieu-qua-va-nhanh-chong\/","title":{"rendered":"5 ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u l\u00f4 \u0111\u1ec1 hi\u1ec7u qu\u1ea3 v\u00e0 nhanh ch\u00f3ng"},"content":{"rendered":"
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C\u00e1ch \u0111\u00e1nh l\u00f4 theo ng\u00e0y nh\u01b0 th\u1ebf n\u00e0o ch\u00ednh x\u00e1c, c\u00f9ng ch\u00fang t\u00f4i t\u00ecm hi\u1ec3u chi ti\u1ebft 5 ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u l\u00f4 \u0111\u1ec1 hi\u1ec7u qu\u1ea3 v\u00e0 nhanh ch\u00f3ng t\u00ecm ra con s\u1ed1 may m\u1eafn, d\u1ec5 tr\u00fang trong ngay qua chia s\u1ebb t\u1eeb cao th\u1ee7 sau \u0111\u00e2y.<\/p>\n\n\n\n
C\u00f3 kh\u00e1 nhi\u1ec1u ng\u01b0\u1eddi soi c\u1ea7u l\u00f4 \u0111\u1ec1 b\u1eaft \u0111\u1ea7u vi\u1ec7c s\u1eed d\u1ee5ng ph\u01b0\u01a1ng ph\u00e1p t\u00ednh x\u00e1c su\u1ea5t qua ng\u00e0y \u00e2m. \u0110\u00e2y c\u0169ng ch\u00ednh kinh nghi\u1ec7m s\u01b0\u01a1ng m\u00e1u \u0111\u01b0\u1ee3c nhi\u1ec1u cao th\u1ee7 truy\u1ec1n th\u1ee5 l\u1ea1i cho ng\u01b0\u1eddi ch\u01a1i. \u01afu \u0111i\u1ec3m c\u1ee7a c\u00e1ch \u0111\u00e1nh n\u00e0y \u0111\u00f3 ch\u00ednh l\u00e0 kh\u1ea3 n\u0103ng x\u1ea3y ra cao. C\u1ee5 th\u1ec3 nh\u01b0 sau:<\/p>\n\n\n\n
V\u00ed d\u1ee5 c\u1ee5 th\u1ec3 cho c\u00e1ch \u0111\u00e1nh n\u00e0y: Ng\u01b0\u1eddi ch\u01a1i \u0111\u00e1nh theo ng\u00e0y \u00e2m trong ng\u00e0y. V\u00ed d\u1ee5 h\u00f4m nay l\u00e0 ng\u00e0y 14\/02\/2024 t\u1ee9c ng\u00e0y 3\/1\/2024 \u00e2m l\u1ecbch ta \u0111\u01b0\u1ee3c ng\u00e0y Qu\u00fd T\u1ef5, ta \u0111\u00e1nh con 16.<\/p>\n\n\n\n
L\u01b0u \u00fd: C\u00e1ch \u0111\u00e1nh n\u00e0y n\u00ean s\u1eed d\u1ee5ng cho c\u00e1c ng\u00e0y \u00e2m \u0111\u1eb7c bi\u1ec7t nh\u01b0 m\u00f9ng 1, r\u1eb1m, gi\u1ed7 t\u1ed5, vu lan,\u2026<\/p>\n\n\n\n
V\u1edbi c\u00e1ch \u0111\u00e1nh n\u00e0y, ng\u01b0\u1eddi ch\u01a1i c\u1ea7n ch\u00fa \u00fd v\u1ec1 con l\u00f4 2,3 nh\u00e1y trong ng\u00e0y. Theo d\u00e2n gian th\u00ec nh\u1eefng con l\u00f4 v\u1ec1 2,3 nh\u00e1y s\u1ebd c\u01b0\u1edbp \u0111i m\u1ea5y ch\u1ed7 \u0111\u1ee9ng c\u1ee7a nh\u1eefng con s\u1ed1 kh\u00e1c. Ch\u00ednh v\u00ec v\u1eady, t\u00ednh to\u00e1n theo quy lu\u1eadt b\u00f9 tr\u1eeb, nh\u01b0ng con s\u1ed1 g\u1ea7n 2,3 nh\u00e1y s\u1ebd v\u1ec1 r\u1ea5t cao.<\/p>\n\n\n\n
V\u00ed d\u1ee5: Ng\u01b0\u1eddi ch\u01a1i \u0111\u00e1nh l\u00f4 10 v\u1ec1 2 nh\u00e1y. Ch\u00fang ta theo d\u00f5i th\u00ec k\u1ebft qu\u1ea3 ng\u00e0y mai ra 11, ng\u00e0y khi l\u1ea1i v\u1ec1 con l\u00f4 12. N\u1ebfu h\u00f4m nay v\u1ec1 3 nh\u00e1y con 10 th\u00ec ng\u00e0y mai kh\u1ea3 n\u0103ng v\u1ec1 09 ho\u1eb7c ng\u00e0y k\u1ebf ti\u1ebfp ta \u0111\u00e1nh con 08. C\u1ee9 theo quy t\u1eafc n\u00e0y m\u00e0 b\u1ea1n s\u1ebd t\u00ecm ki\u1ebfm ra con s\u1ed1 ph\u00f9 h\u1ee3p cho m\u00ecnh.<\/p>\n\n\n\n
Tr\u01b0\u1eddng h\u1ee3p n\u1ebfu nh\u01b0 k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1 ra, b\u1ea1n c\u00f3 th\u1ec3 d\u1ef1a v\u00e0o 2 s\u1ed1 cu\u1ed1i c\u1ee7a gi\u1ea3i x\u1ed5 s\u1ed1 \u0111\u1ec3 \u0111\u00e1nh. \u0110\u1ec1 c\u00f3 th\u1ec3 mang v\u1ec1 con l\u00f4 cho ng\u00e0y h\u00f4m sau. V\u1edbi c\u00e1ch ch\u01a1i n\u00e0y kh\u00e1 \u0111\u01a1n gi\u1ea3n, nh\u01b0ng hi\u1ec7u qu\u1ea3 l\u1ea1i c\u1ef1c k\u1ef3 cao, x\u00e1c su\u1ea5t gi\u00e0nh chi\u1ebfn th\u1eafng \u0111\u01b0\u1ee3c \u00e1p d\u1ee5ng v\u1edbi y\u00eau c\u1ea7u sau \u0111\u00e2y:<\/p>\n\n\n\n
B\u1ea1n c\u00f3 th\u1ec3 l\u1ea5y con s\u1ed1 b\u1ea5t k\u1ef3 ho\u1eb7c k\u1ebft qu\u1ea3 b\u1ea5t k\u1ef3 \u0111\u1ec3 ch\u1ecdn ra k\u1ebft qu\u1ea3 \u0111\u1ec3 \u0111\u00e1nh cho ng\u00e0y h\u00f4m sau. Nh\u01b0 v\u1eady, k\u1ebft qu\u1ea3 s\u1ebd cao h\u01a1n n\u1ebfu tr\u01b0\u1ee3t 1 con th\u00ec c\u00f3 th\u1ec3 hy v\u1ecdng v\u00e0o c\u00e1c con s\u1ed1 kh\u00e1c.<\/p>\n\n\n\n
Ng\u01b0\u1eddi ch\u01a1i c\u00f3 th\u1ec3 l\u1ea5y k\u1ebft qu\u1ea3 c\u00e1c gi\u1ea3i nh\u1ea5t, nh\u00ec, 3, 4 , 5, \u2026Nh\u01b0ng l\u01b0u \u00fd c\u00e1c gi\u1ea3i kh\u00e1c nh\u01b0 gi\u1ea3i 7 v\u00e0 \u0111\u1eb7c bi\u1ec7t th\u00ec n\u00ean h\u1ea1n ch\u1ebf \u0111\u1ec3 ph\u00f2ng tr\u01b0\u1eddng h\u1ee3p c\u1ea7u tr\u1ec5. B\u1edfi nh\u1eefng gi\u1ea3i n\u00e0y, c\u00e1c s\u1ed1 ra th\u01b0\u1eddng d\u1ec5 b\u1ecb g\u00e3y, t\u1ef7 l\u1ec7 tr\u00fang th\u1ea5p h\u01a1n.<\/p>\n\n\n\n
B\u1ea1n c\u00f3 th\u1ec3 d\u00f9ng k\u1ebft qu\u1ea3 b\u1ea5t k\u1ef3 gh\u00e9p v\u1edbi nhau \u0111\u1ec3 c\u00f3 \u0111\u01b0\u1ee3c k\u1ebft qu\u1ea3 cho k\u1ef3 sau. Sau \u0111\u00f3 s\u1eed d\u1ee5ng \u0111\u1ec3 d\u00f2 k\u1ebft qu\u1ea3 cho k\u1ef3 sau xem c\u00f3 \u0111\u00fang hay kh\u00f4ng. N\u1ebfu nh\u01b0 \u0111\u00fang, c\u00f3 th\u1ec3 d\u00f9ng \u0111\u1ec3 \u0111\u1ea1n ti\u1ebfp cho k\u1ef3 sau.<\/p>\n\n\n\n
L\u01b0u \u00fd: Ng\u01b0\u1eddi ch\u01a1i ch\u1ec9 n\u00ean ch\u1ecdn nh\u1eefng nh\u1eefng con s\u1ed1 \u0111\u00e3 t\u1eebng \u0103n 3 k\u1ef3 tr\u1edf l\u00ean (c\u1ea7u 3 nh\u1ecbp) \u0111\u1ec3 c\u00f3 t\u1ef7 l\u1ec7 chi\u1ebfn th\u1eafng cao nh\u1ea5t.<\/p>\n\n\n
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C\u00f2n nhi\u00eau s\u1ef1 l\u1ef1a ch\u1ecdn ph\u00f9 h\u1ee3p d\u00e0nh cho ng\u01b0\u1eddi ch\u01a1i n\u1ebfu ch\u1ecdn \u0111\u00e1nh theo ng\u00e0y d\u1ef1a v\u00e0o c\u00e1c th\u1ee9 c\u1ef1c k\u1ef3 chu\u1ea9n x\u00e1c. Ng\u01b0\u01a1i ch\u01a1i c\u00f3 th\u1ec3 \u00e1p d\u1ee5ng cho c\u00e1ch t\u00ednh nh\u01b0 sau:<\/p>\n\n\n\n
Ng\u01b0\u1eddi ch\u01a1i s\u1eed d\u1ee5ng t\u1ed5ng \u0111\u1ec1 ng\u00e0y th\u1ee9 2, nu\u00f4i trong 3 ng\u00e0y: Th\u1ee9 3,4,5<\/p>\n\n\n\n
B\u1ea1n ch\u1ecdn nu\u00f4i t\u1ed5ng \u0111\u1ec1 ng\u00e0y th\u1ee9 5 \u0111\u1ec3 nu\u00f4i ti\u1ebfp trong 3 ng\u00e0y \u0111\u00f3 l\u00e0 th\u1ee9 6,7 v\u00e0 ch\u1ee7 nh\u1eadt.<\/p>\n\n\n\n
V\u00ed d\u1ee5: Ng\u00e0y th\u1ee9 2, \u0111\u1ec1 v\u1ec1 con 83 th\u00ec t\u1ed5ng \u0111\u1ec1 c\u1ed9ng l\u1ea1i l\u00e0 11. B\u1ea1n s\u1ebd nu\u00f4i con s\u1ed1 n\u00e0y trong 3 ng\u00e0y. Th\u01b0\u1eddng ng\u00e0y th\u1ee9 3 ho\u1eb7c th\u1ee9 4 s\u1ebd ra l\u1ea1i con l\u00f4 n\u00e0y. N\u1ebfu h\u1ebft 3 ng\u00e0y v\u1eabn ch\u01b0a ra th\u00ec b\u1ecf qua con s\u1ed1 n\u00e0y.<\/p>\n\n\n\n
N\u1ebfu trong ng\u00e0y th\u1ee9 5 l\u00f4 \u0111\u1ec1 v\u1ec1 con 48, c\u00f3 t\u1ed5ng \u0111\u1ec1 l\u00e0 12 th\u00ec ta c\u0169ng c\u00f3 \u0111\u01b0\u1ee3c c\u1eb7p s\u1ed1 12-21. C\u00f2n t\u1ed5ng \u0111\u1ec1 cho ng\u00e0y th\u1ee9 2 con 11 th\u00ec ch\u1ee7 nh\u1eadt s\u1ebd v\u1ec1 21 ho\u1eb7c 11.<\/p>\n\n\n\n
\u0110\u00e2y l\u00e0 ph\u01b0\u01a1ng ph\u00e1p ch\u01a1i kh\u00e1 hay. C\u00e1ch n\u00e0y \u0111\u01b0\u1ee3c c\u00e1c chuy\u00ean gia s\u1eed d\u1ee5ng \u0111\u1ec3 soi ra con s\u1ed1 ch\u00ednh x\u00e1c d\u1ef1a v\u00e0o phong th\u1ee7y. Hay n\u00f3i c\u00e1ch kh\u00e1c l\u00e0 d\u1ef1a v\u00e0o b\u00f3ng \u00e2m d\u01b0\u01a1ng c\u1ee7a c\u00e1c con s\u1ed1 \u0111\u1ec3 t\u00ednh qua phong th\u1ee7y ng\u0169 h\u00e0nh, t\u01b0\u01a1ng sinh, t\u01b0\u01a1ng kh\u1eafc.<\/p>\n\n\n\n
Quy lu\u1eadt ng\u0169 h\u00e0nh nh\u01b0 sau: Kim \u2013 M\u1ed9c \u2013 H\u1ecfa \u2013 Th\u1ee7y \u2013 Th\u1ed5<\/p>\n\n\n\n
+ T\u01b0\u01a1ng sinh: Kim \u2013 Th\u1ee7y, Th\u1ee7y \u2013 M\u1ed9c, M\u1ed9c \u2013 H\u1ecfa, H\u1ecfa \u2013 Th\u1ed5, Th\u1ed5 \u2013 Kim.<\/p>\n\n\n\n
+ T\u01b0\u01a1ng kh\u1eafc: Kim kh\u1eafc M\u1ed9c, M\u1ed9c kh\u1eafc Th\u1ed5, Th\u1ed5 kh\u1eafc Th\u1ee7y, Th\u1ee7y kh\u1eafc H\u1ecfa, H\u1ecfa kh\u1eafc Kim.<\/p>\n\n\n\n
Quy t\u1eafc b\u00f3ng \u00e2m d\u01b0\u01a1ng:<\/p>\n\n\n\n
+ B\u00f3ng D\u01b0\u01a1ng: 1 \u2013 6; 2 \u2013 7; 3 \u2013 8; 4 \u2013 9; 5 \u2013 0.<\/p>\n\n\n\n
+ B\u00f3ng \u00c2m: 1 \u2013 4; 2 \u2013 9; 3 \u2013 6; 5 \u2013 8; 0 \u2013 7.<\/p>\n\n\n\n
Quy \u01b0\u1edbc trong ng\u0169 h\u00e0nh theo c\u00e1c con s\u1ed1 sau:<\/p>\n\n\n\n
Th\u1ee7y = 1, Kim = 2, H\u1ecfa = 3, Th\u1ed5 = 4, M\u1ed9c = 5.<\/p>\n\n\n\n
Ta t\u00ednh \u0111\u01b0\u1ee3c b\u00f3ng ng\u0169 h\u00e0nh: Th\u1ee7y = 6, Kim = 7, H\u1ecfa = 8, Th\u1ed5 = 9, M\u1ed9c = 0.<\/p>\n\n\n\n
V\u00ed d\u1ee5 gi\u1ea3i \u0111\u1eb7c bi\u1ec7t An Gian l\u00e0 con 26. T\u1eeb \u0111\u00f3 ta t\u00ednh ra \u0111\u01b0\u1ee3c:<\/p>\n\n\n\n
\u21d2 26 theo b\u00f3ng d\u01b0\u01a1ng l\u00e0 7 v\u00e0 1 => \u0111\u01b0\u1ee3c c\u1ea7u 17 \u2013 71.<\/p>\n\n\n\n
\u21d2 26 t\u00ednh theo b\u00f3ng \u00e2m l\u00e0 9 v\u00e0 3 => \u0110\u00e1nh con c\u1ea7u 93 \u2013 39.<\/p>\n\n\n\n
Ch\u00fac c\u00e1c b\u1ea1n th\u00e0nh c\u00f4ng!<\/p>\n\n\n
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C\u00e1ch \u0111\u00e1nh l\u00f4 theo ng\u00e0y nh\u01b0 th\u1ebf n\u00e0o ch\u00ednh x\u00e1c, c\u00f9ng ch\u00fang t\u00f4i t\u00ecm hi\u1ec3u chi ti\u1ebft 5 ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u l\u00f4 \u0111\u1ec1 hi\u1ec7u qu\u1ea3 v\u00e0 nhanh ch\u00f3ng t\u00ecm ra con s\u1ed1 may m\u1eafn, d\u1ec5 tr\u00fang trong ngay qua chia Continue reading 5 ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u l\u00f4 \u0111\u1ec1 hi\u1ec7u qu\u1ea3 v\u00e0 nhanh ch\u00f3ng<\/span>